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when tested the lives (in hours) of 5 b...

when tested the lives (in hours) of 5 bulbs were noted as follows 1357,1090,1666,1494,1623
The mean deviations (in hours ) from their mean is

A

178

B

179

C

220

D

356

Text Solution

AI Generated Solution

The correct Answer is:
To find the mean deviation from the mean for the lives of the 5 bulbs (1357, 1090, 1666, 1494, 1623), we will follow these steps: ### Step 1: Calculate the Mean (x̄) To find the mean, we sum all the values and divide by the number of observations. \[ x̄ = \frac{\text{Sum of all values}}{n} \] Where: - Sum of all values = 1357 + 1090 + 1666 + 1494 + 1623 - n = 5 (the number of bulbs) Calculating the sum: \[ 1357 + 1090 + 1666 + 1494 + 1623 = 7230 \] Now, calculate the mean: \[ x̄ = \frac{7230}{5} = 1446 \] ### Step 2: Calculate the Deviations from the Mean Next, we calculate the absolute deviations of each value from the mean. \[ d_i = |x_i - x̄| \] Where \(x_i\) are the individual bulb lives: - For 1357: \(d_1 = |1357 - 1446| = | -89 | = 89\) - For 1090: \(d_2 = |1090 - 1446| = | -356 | = 356\) - For 1666: \(d_3 = |1666 - 1446| = | 220 | = 220\) - For 1494: \(d_4 = |1494 - 1446| = | 48 | = 48\) - For 1623: \(d_5 = |1623 - 1446| = | 177 | = 177\) ### Step 3: Sum the Absolute Deviations Now we sum all the absolute deviations: \[ \text{Sum of deviations} = d_1 + d_2 + d_3 + d_4 + d_5 = 89 + 356 + 220 + 48 + 177 \] Calculating the sum: \[ 89 + 356 + 220 + 48 + 177 = 890 \] ### Step 4: Calculate the Mean Deviation Finally, we calculate the mean deviation by dividing the sum of deviations by the number of observations. \[ \text{Mean Deviation} = \frac{\text{Sum of deviations}}{n} = \frac{890}{5} = 178 \] ### Final Answer The mean deviation from their mean is **178 hours**. ---

To find the mean deviation from the mean for the lives of the 5 bulbs (1357, 1090, 1666, 1494, 1623), we will follow these steps: ### Step 1: Calculate the Mean (x̄) To find the mean, we sum all the values and divide by the number of observations. \[ x̄ = \frac{\text{Sum of all values}}{n} \] ...
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