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evaluate: |(x^(2)-x+1, x-1),(x+1,x+1)|...

evaluate: `|(x^(2)-x+1, x-1),(x+1,x+1)|`

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The correct Answer is:
N/a
We have `|(x^(2)-x+1, x-1),(x+1,x+1)|=|(x^(2)-2x+2,x-1),(0,x+1)|` [ ` :'C_(1)toC_(1)-C_(2)`]
`=(x^(2)-2x+2).(x+1)-(x-1).0`
`x^(3)-2x^(2)+2x+x^(2)-2x+2`
`=x^(3)-2x^(2)+2x+x^(2)-2x+2`
`=x^(3)-x^(2)+2`
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