If `A` is a matrix of order `3xx3` then the number of minors in determinant of `A` are…………………….

Explanation

To find the number of minors in the determinant of a matrix \( A \) of order \( 3 \times 3 \), we will follow these steps:

### Step 1: Understanding the Definition of Minor
A minor of an element in a matrix is defined as the determinant of the submatrix that remains after removing the row and column of that element.

**Hint:** Remember that a minor is associated with each element of the matrix.

### Step 2: Identify the Elements of the Matrix
For a \( 3 \times 3 \) matrix \( A \), it has 9 elements. We can denote the matrix as follows:
\[ A = \begin{pmatrix} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33} \end{pmatrix} \]

**Hint:** Count the total number of elements in a \( 3 \times 3 \) matrix.

### Step 3: Calculate the Number of Minors
Since each of the 9 elements in the \( 3 \times 3 \) matrix has a corresponding minor, we can conclude that there are a total of 9 minors.

**Hint:** Each element contributes one minor, so the total number of minors equals the number of elements.

### Step 4: Conclusion
Thus, the total number of minors in the determinant of matrix \( A \) is 9.

**Final Answer:** The number of minors in the determinant of \( A \) is **9**.