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If x = t^(2) and y = t^(3), then (d^(2)y...

If `x = t^(2)` and `y = t^(3)`, then `(d^(2)y)/(dx^(2))` is equal to

A

`3/2`

B

`3/(4t)`

C

`3/(2t)`

D

`(3)/(2t)`

Text Solution

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The correct Answer is:
To find \(\frac{d^2y}{dx^2}\) given \(x = t^2\) and \(y = t^3\), we will follow these steps: ### Step 1: Differentiate \(x\) and \(y\) with respect to \(t\) 1. Start with the equations: \[ x = t^2 \quad \text{and} \quad y = t^3 \] 2. Differentiate \(x\) with respect to \(t\): \[ \frac{dx}{dt} = 2t \] 3. Differentiate \(y\) with respect to \(t\): \[ \frac{dy}{dt} = 3t^2 \] ### Step 2: Find \(\frac{dy}{dx}\) 4. Use the chain rule to find \(\frac{dy}{dx}\): \[ \frac{dy}{dx} = \frac{dy/dt}{dx/dt} = \frac{3t^2}{2t} = \frac{3t}{2} \] ### Step 3: Differentiate \(\frac{dy}{dx}\) with respect to \(x\) 5. To find \(\frac{d^2y}{dx^2}\), we need to differentiate \(\frac{dy}{dx}\) with respect to \(x\): \[ \frac{d^2y}{dx^2} = \frac{d}{dx}\left(\frac{dy}{dx}\right) \] 6. Since \(\frac{dy}{dx} = \frac{3t}{2}\), we can express this differentiation in terms of \(t\): \[ \frac{d^2y}{dx^2} = \frac{d}{dt}\left(\frac{3t}{2}\right) \cdot \frac{dt}{dx} \] ### Step 4: Calculate \(\frac{dt}{dx}\) 7. From our earlier calculation, we know: \[ \frac{dx}{dt} = 2t \implies \frac{dt}{dx} = \frac{1}{2t} \] ### Step 5: Substitute and simplify 8. Now substitute \(\frac{dt}{dx}\) into the expression for \(\frac{d^2y}{dx^2}\): \[ \frac{d^2y}{dx^2} = \left(\frac{3}{2}\right) \cdot \frac{1}{2t} = \frac{3}{4t} \] ### Final Answer Thus, the final result is: \[ \frac{d^2y}{dx^2} = \frac{3}{4t} \]

To find \(\frac{d^2y}{dx^2}\) given \(x = t^2\) and \(y = t^3\), we will follow these steps: ### Step 1: Differentiate \(x\) and \(y\) with respect to \(t\) 1. Start with the equations: \[ x = t^2 \quad \text{and} \quad y = t^3 \] 2. Differentiate \(x\) with respect to \(t\): ...
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