The oxide that gives `H_(2)O_(2)` on treatment with dilute `H_(2)S0_(4)` is

Options

A. `PbO_(2)`
B. `BaO_(2).8H_(2)O + O_(2)`
C. `MnO_(2)`
D. `TiO_(2)`

Explanation

To solve the question regarding which oxide gives H₂O₂ when treated with dilute H₂SO₄, we can follow these steps:

### Step 1: Identify the Oxides
We need to identify the oxides that are capable of producing hydrogen peroxide (H₂O₂) when reacted with dilute sulfuric acid (H₂SO₄).

### Step 2: Understand the Concept of Peroxy Linkage
The key to this question is understanding that certain oxides contain a peroxy linkage (O-O bond). Oxides such as BaO₂ (barium peroxide) and Na₂O₂ (sodium peroxide) contain this peroxy linkage and are known to produce H₂O₂ upon reaction with dilute H₂SO₄.

### Step 3: Reaction with Dilute H₂SO₄
When these peroxides react with dilute sulfuric acid, they decompose to form hydrogen peroxide. The general reaction can be represented as:
\[ \text{BaO}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{BaSO}_4 + \text{H}_2\text{O}_2 \]

### Step 4: Analyze Other Oxides
Other oxides like PbO₂ (lead dioxide), MnO₂ (manganese dioxide), and TiO₂ (titanium dioxide) do not contain the peroxy linkage and therefore do not produce hydrogen peroxide when treated with dilute H₂SO₄.

### Step 5: Conclusion
From the analysis, we conclude that the oxide that gives H₂O₂ on treatment with dilute H₂SO₄ is BaO₂ (barium peroxide).

### Final Answer
The oxide that gives H₂O₂ on treatment with dilute H₂SO₄ is **BaO₂**.

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