When sodium peroxide is trated with the dilute sulphuric acid, we get……..

Options

A. sodium sulphate and water
B. sodium sulphate and oxygen
C. sodium sulphate, hydrogen and oxygen
D. sodium sulphate and hydrogen peroxide

Explanation

To solve the question, we need to understand the reaction between sodium peroxide (Na2O2) and dilute sulfuric acid (H2SO4). Here are the steps to derive the answer:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Sodium peroxide (Na2O2)
- Dilute sulfuric acid (H2SO4)

2. **Write the Chemical Reaction**:
- When sodium peroxide reacts with dilute sulfuric acid, the reaction can be represented as:
\[ \text{Na}_2\text{O}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{Na}_2\text{SO}_4 + \text{H}_2\text{O}_2 \]
- Here, sodium sulfate (Na2SO4) and hydrogen peroxide (H2O2) are produced.

3. **Balance the Reaction**:
- Check the number of atoms on both sides of the equation:
- Sodium (Na): 2 on both sides
- Sulfur (S): 1 on both sides
- Oxygen (O): 4 from Na2O2 and 4 from H2SO4 (total 8) on the left side, and 4 from Na2SO4 and 2 from H2O2 (total 6) on the right side.
- Hydrogen (H): 2 from H2SO4 and 2 from H2O2 (total 4) on the right side.
- The equation is balanced as written.

4. **Identify the Products**:
- From the balanced equation, we see that the products are sodium sulfate (Na2SO4) and hydrogen peroxide (H2O2).

5. **Select the Correct Option**:
- The question provides multiple-choice answers. The correct answer based on our reaction is:
- Sodium sulfate and hydrogen peroxide.

### Final Answer:
When sodium peroxide is treated with dilute sulfuric acid, we get sodium sulfate and hydrogen peroxide.

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