If A; B are invertible matrices of the same order; then show that `(AB)^-1 = B^-1 A^-1`

Explanation

To show that \((AB)^{-1} = B^{-1} A^{-1}\) for invertible matrices \(A\) and \(B\), we can follow these steps:

### Step 1: Start with the product of the matrices
We know that if \(A\) and \(B\) are invertible matrices, then the product \(AB\) is also invertible. We want to find the inverse of the product \(AB\).

### Step 2: Use the property of the identity matrix
By the definition of the inverse, we know that:
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