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The function f(x) =cot x is discontinu...

The function `f(x) =cot x` is discontinuous on set

A

`{x=npi:ninZ }`

B

`{x = 2npi : n in Z }`

C

` {x =(2n+1)(pi)/(2),n in Z}`

D

`{x=(npi)/(2), n in Z}`

Text Solution

Verified by Experts

The correct Answer is:
A
We know that, `f(x) = cotx` is continuous in `R-{npi:ninZ}`.
Since, `f(x) = cotx = (cosx)/(sinx)`, [since, `sinx = 0` at `n pi, n in Z`]
Hence`f(x)= cotx` is discontinuous on the set ` {x=npi : n in Z}`.
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