Home
Class 12
MATHS
Find the area of the region bounded by t...

Find the area of the region bounded by the curve `y^(2)=9x" and " y=3x`.

Text Solution

Verified by Experts

The correct Answer is:
N/a

We, have `y^(2)9x" and " y=3x`
`rarr(3x)^(2)=9x`
`rArr"9x^(2)-9x=0`
`rArr9x(x-1)=0`
`rArrx=1, 0`

`:."Required area, " A =int_(0)^(1)sqrt(9xcx)-int_(0)^(1)3xdx`
`=3int_(0)^(1)x^(1//2)dx-3int_(0)^(1)xdx`
`=3[(x^(3//2))/(3//2)]_(0)^(1)-3[(x^(2))/2]_(0)^(1)`
`=3(2/3-0)-3(1/2-0)`
`=2-3/2=1/2" sq units"`
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Questions|16 Videos
  • APPLICATION OF INTEGRALS

    NCERT EXEMPLAR ENGLISH|Exercise Objective Type Questions|22 Videos
  • APPLICATION OF DERIVATIVES

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|5 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    NCERT EXEMPLAR ENGLISH|Exercise True/False|10 Videos

Similar Questions

Explore conceptually related problems

Find the area of the region bounded by the curve y^(2)=4x" and " x^(2)=4y .

Find the area of the region bounded by the curve y^(2)=4x" and " x^(2)=4y .

Find the area of the region bounded by the curve y^(2)=2x" and "x^(2)+y^(2)=4x .

Find the area of the region bounded by the curve y=x^(3),y=x+6" and "x=0

Find the area of the region bounded by the curves y^(2)=x+1 and y^(2)= -x +1 .

Find the area of the region bounded by the curves x=2y-y^2 and y=2+x .

Using integration, find the area of the region bounded by the curves y=x and y=x^(3) .

Find the area of the region bounded by the curves x=|y^(2)-1| and y=x-5 .

Find the area of the region bounded by the curve y^2=4x and the line x = 3 .

Find the area of the region bounded by the curve y^2= x and the lines x = 1, x = 4 and the x-axis.

NCERT EXEMPLAR ENGLISH-APPLICATION OF INTEGRALS-Objective Type Questions
  1. Find the area of the region bounded by the curve y^(2)=9x" and " y=3x.

    Text Solution

    |

  2. The area of the region bounded by the Y-"axis" y = "cos" x and y = "si...

    Text Solution

    |

  3. The area of the region bounded by the curve x^(2)=4y and the straight ...

    Text Solution

    |

  4. The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axi...

    Text Solution

    |

  5. Find the area of the region in the first quadrant enclosed by the y-ax...

    Text Solution

    |

  6. Area of the regionbounded by the curve y = "cos" x between x = 0 and x...

    Text Solution

    |

  7. The area of the region bounded by parabola y^(2)=x and the straight li...

    Text Solution

    |

  8. The area of the region bounded by the curve y = "sin" x between the or...

    Text Solution

    |

  9. The area of the region bounded by the ellipse (x^(2))/25+y^(2)/16=1 is

    Text Solution

    |

  10. The area of the region by the circle x^(2)+y^(2)=1 is

    Text Solution

    |

  11. The area of the region bounded by the curve y = x + 1 and the lines x=...

    Text Solution

    |

  12. The area of the region bounded by the curve x=2y+3 and the lines y=1, ...

    Text Solution

    |

  13. The area of the region bounded by the Y-"axis" y = "cos" x and y = "si...

    Text Solution

    |

  14. Using integration, find the area bounded by the curve x^2=4y and the l...

    Text Solution

    |

  15. The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axi...

    Text Solution

    |

  16. Area of the region in the first quadrant exclosed by the X-axis, the l...

    Text Solution

    |

  17. Area of the regionbounded by the curve y = "cos" x between x = 0 and x...

    Text Solution

    |

  18. The area of the region bounded by parabola y^(2)=x and the straight li...

    Text Solution

    |

  19. The area of the region bounded by the curve y = "sin" x between the or...

    Text Solution

    |

  20. The area of the region bounded by the ellipse (x^(2))/25+y^(2)/16=1 is

    Text Solution

    |

  21. The area of the region by the circle x^(2)+y^(2)=1 is

    Text Solution

    |