Home
Class 12
MATHS
Sketch the region {(x, 0):y=sqrt(4-x^(2)...

Sketch the region `{(x, 0):y=sqrt(4-x^(2))}` and X-axis. Find the area of the region using integration.

Text Solution

Verified by Experts

The correct Answer is:
N/a

Given region is `{(x, 0):y=sqrt(4-x^(2))}` and X-axis.
We have, `y=sqrt(4-x^(2))rArry^(2)=4-x^(2)rArrx^(2)+y^(2)=4`

`:." Area of shaded region, "A=int_(-2)^(2)sqrt(4-x^(2))dx=int_(-2)^(2)sqrt(2^(2)-x^(2))dx`
`=[x/2sqrt(2^(2)-x^(2))+(2^(2))/2 .sin^(-1)(x)/2]_(-2)^(2)`
`=2/2 .0+0. pi/2+2/2 .0-2sin^(-1)(-1)=2. pi/2+2. pi/2`
`=2pi" sq units"`
Promotional Banner

Topper's Solved these Questions

  • APPLICATION OF INTEGRALS

    NCERT EXEMPLAR ENGLISH|Exercise Long Answer Type Questions|16 Videos
  • APPLICATION OF INTEGRALS

    NCERT EXEMPLAR ENGLISH|Exercise Objective Type Questions|22 Videos
  • APPLICATION OF DERIVATIVES

    NCERT EXEMPLAR ENGLISH|Exercise Fillers|5 Videos
  • CONTINUITY AND DIFFERENTIABILITY

    NCERT EXEMPLAR ENGLISH|Exercise True/False|10 Videos

Similar Questions

Explore conceptually related problems

Sketch the region |(x , y):9x^2+4y^2=36| and find the area of the region enclosed by it using integration.

Sketch the region for y=sin(x-[x]) .

Sketch the region common to the circle x^2+y^2=16 and the parabols x^2=6ydot Also find the area of the region using integration.

Sketch the region bounded by y=2x-x^2 and x-axis and find its area using integration.

Sketch the region lying in the first quadrant and bounded by y=9x^2, x=0,y=1a n dy=4. Find the area of the region using integration.

Draw a rough sketch of the region {(x , y): y^2lt=5x ,\ 5x^2+5y^2lt=36} and find the area enclosed by the region using method of integration

Draw a rough sketch of the region {(x,y): y^2 le 3x,3x^2 + 3y^2 le16 } and find the area enclosed by the region using the method of integration

Draw the graphs of 2x+y=6 and 2x-y+2=0 . Shade the region bounded by these lines and x-axis. Find the area of the shaded region.

Solve the following system of linear equations graphically: x+y-11=0,\ \ \ x-y-1=0 . Shade the region bounded by these lines and y-axis. Also, find the area of the region bounded by these lines and y-axis.

Draw a rough sketch of the region {(x,y) : y^(2)le 6 a x and x^(2)+y^(2)le 16 a^(2)} . Also, find the area of the region sketched using method of integration.

NCERT EXEMPLAR ENGLISH-APPLICATION OF INTEGRALS-Objective Type Questions
  1. Sketch the region {(x, 0):y=sqrt(4-x^(2))} and X-axis. Find the area o...

    Text Solution

    |

  2. The area of the region bounded by the Y-"axis" y = "cos" x and y = "si...

    Text Solution

    |

  3. The area of the region bounded by the curve x^(2)=4y and the straight ...

    Text Solution

    |

  4. The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axi...

    Text Solution

    |

  5. Find the area of the region in the first quadrant enclosed by the y-ax...

    Text Solution

    |

  6. Area of the regionbounded by the curve y = "cos" x between x = 0 and x...

    Text Solution

    |

  7. The area of the region bounded by parabola y^(2)=x and the straight li...

    Text Solution

    |

  8. The area of the region bounded by the curve y = "sin" x between the or...

    Text Solution

    |

  9. The area of the region bounded by the ellipse (x^(2))/25+y^(2)/16=1 is

    Text Solution

    |

  10. The area of the region by the circle x^(2)+y^(2)=1 is

    Text Solution

    |

  11. The area of the region bounded by the curve y = x + 1 and the lines x=...

    Text Solution

    |

  12. The area of the region bounded by the curve x=2y+3 and the lines y=1, ...

    Text Solution

    |

  13. The area of the region bounded by the Y-"axis" y = "cos" x and y = "si...

    Text Solution

    |

  14. Using integration, find the area bounded by the curve x^2=4y and the l...

    Text Solution

    |

  15. The area of the region bounded by the curve y=sqrt(16-x^(2)) and X-axi...

    Text Solution

    |

  16. Area of the region in the first quadrant exclosed by the X-axis, the l...

    Text Solution

    |

  17. Area of the regionbounded by the curve y = "cos" x between x = 0 and x...

    Text Solution

    |

  18. The area of the region bounded by parabola y^(2)=x and the straight li...

    Text Solution

    |

  19. The area of the region bounded by the curve y = "sin" x between the or...

    Text Solution

    |

  20. The area of the region bounded by the ellipse (x^(2))/25+y^(2)/16=1 is

    Text Solution

    |

  21. The area of the region by the circle x^(2)+y^(2)=1 is

    Text Solution

    |