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Find the area of region by the curve y=s...

Find the area of region by the curve `y=sinx" between "x=0" and "x=2pi`.

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The correct Answer is:
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Required area `=int_(0)^(2pi)sinx dx =int_(0)^(pi)sinx sx +abs(int_(pi)^(2pi)sinx dx)`
`-[cosc]_(0)^(pi)+abs([-cosx]_(pi)^(2pi))`
`=-[cospi-cos0]+abs(-[cos2pi-cospi])`

`=-[-1-1]+ABS(-(1+1))`
`=2+2=4" sq units "`
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