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If dy/dx=e^(-2y) and y=0 when x=5, then ...

If `dy/dx=e^(-2y) and y=0` when `x=5,` then the value of x for `y=3` is

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To solve the differential equation given by \( \frac{dy}{dx} = e^{-2y} \) with the initial condition \( y = 0 \) when \( x = 5 \), and to find the value of \( x \) for \( y = 3 \), we will follow these steps: ### Step 1: Separate the Variables We start by separating the variables in the differential equation: \[ \frac{dy}{dx} = e^{-2y} \] This can be rewritten as: ...
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(dy)/(dx)+(x-2y)/(2x-y)=0