Find the equation of the curve through the point (1,0), if the slope of the tangent to the curve at any point (x,y) is `(y-1)/(x^(2)+x)`

Explanation

To find the equation of the curve through the point (1, 0), given that the slope of the tangent to the curve at any point (x, y) is \(\frac{y-1}{x^2+x}\), we can follow these steps:

### Step 1: Set up the differential equation
We start with the given slope of the tangent, which can be expressed as:
\[ \frac{dy}{dx} = \frac{y - 1}{x^2 + x} \]

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