Find the equation of the curve passing through origin if the slope of the tangent to the curve at any point `(x ,y)i s` equal to the square of the difference of the abscissa and ordinate of the point.

Explanation

To find the equation of the curve passing through the origin, given that the slope of the tangent to the curve at any point \((x, y)\) is equal to the square of the difference of the abscissa and ordinate of the point, we can follow these steps:

### Step 1: Set up the differential equation
The slope of the tangent to the curve is given by \(\frac{dy}{dx}\). According to the problem, this slope is equal to the square of the difference between \(x\) and \(y\):
\[ \frac{dy}{dx} = (x - y)^2 \]

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