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The solution of differential equation xd...

The solution of differential equation xdy-ydx=0 represents

A

a reactangular hyperbola

B

parabola whose vertex is at orgin

C

straight line passing through origin

D

a circle whose centre is at origin

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To solve the differential equation \( xdy - ydx = 0 \) and determine what it represents, we can follow these steps: ### Step 1: Rewrite the equation We start with the given differential equation: \[ xdy - ydx = 0 \] We can rearrange this to: \[ xdy = ydx \] ### Step 2: Separate the variables Next, we separate the variables by dividing both sides by \( y \) and \( x \): \[ \frac{dy}{y} = \frac{dx}{x} \] ### Step 3: Integrate both sides Now, we integrate both sides: \[ \int \frac{dy}{y} = \int \frac{dx}{x} \] The integrals yield: \[ \log |y| = \log |x| + C \] where \( C \) is the constant of integration. ### Step 4: Simplify the equation Using the properties of logarithms, we can rewrite the equation: \[ \log |y| = \log |x| + \log |c| \] This can be combined into: \[ \log |y| = \log |cx| \] where \( c = e^C \) is a positive constant. ### Step 5: Exponentiate both sides Exponentiating both sides to eliminate the logarithm gives: \[ |y| = |cx| \] This implies: \[ y = cx \] where \( c \) can be any real number (positive or negative). ### Step 6: Conclusion The equation \( y = cx \) represents a family of straight lines passing through the origin. ### Final Answer The solution of the differential equation \( xdy - ydx = 0 \) represents a family of straight lines passing through the origin. ---

To solve the differential equation \( xdy - ydx = 0 \) and determine what it represents, we can follow these steps: ### Step 1: Rewrite the equation We start with the given differential equation: \[ xdy - ydx = 0 \] We can rearrange this to: ...
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