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The differential equation y(dy)/(dx)+x=C...

The differential equation `y(dy)/(dx)+x=C` represents

A

family of hyperbolas

B

family of parabolas

C

family of ellipses

D

family of circles

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To solve the differential equation \( y \frac{dy}{dx} + x = C \) and determine what it represents, we can follow these steps: ### Step 1: Rearranging the Equation We start with the given differential equation: \[ y \frac{dy}{dx} + x = C \] We can rearrange this to isolate the term involving \( \frac{dy}{dx} \): \[ y \frac{dy}{dx} = C - x \] ### Step 2: Separating Variables Next, we separate the variables \( y \) and \( x \): \[ y \, dy = (C - x) \, dx \] ### Step 3: Integrating Both Sides Now, we integrate both sides: \[ \int y \, dy = \int (C - x) \, dx \] Calculating the left side: \[ \int y \, dy = \frac{y^2}{2} \] Calculating the right side: \[ \int (C - x) \, dx = Cx - \frac{x^2}{2} + k \] where \( k \) is the constant of integration. ### Step 4: Combining the Results Now we equate the results of the integrations: \[ \frac{y^2}{2} = Cx - \frac{x^2}{2} + k \] To simplify, we can multiply the entire equation by 2: \[ y^2 = 2Cx - x^2 + 2k \] ### Step 5: Rearranging into Standard Form Rearranging gives us: \[ y^2 + x^2 - 2Cx - 2k = 0 \] This can be rewritten as: \[ y^2 + (x - C)^2 = C^2 + 2k \] This equation represents a family of circles centered at \( (C, 0) \) with radius \( \sqrt{C^2 + 2k} \). ### Conclusion Thus, the differential equation \( y \frac{dy}{dx} + x = C \) represents a family of circles. ---

To solve the differential equation \( y \frac{dy}{dx} + x = C \) and determine what it represents, we can follow these steps: ### Step 1: Rearranging the Equation We start with the given differential equation: \[ y \frac{dy}{dx} + x = C \] We can rearrange this to isolate the term involving \( \frac{dy}{dx} \): ...
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