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The differential equation for which y=a ...

The differential equation for which `y=a cos x+b sin x` is a solution is

A

`(d^(2)y)/(dx^(2))+y=0`

B

`(d^(2)y)/(dx^(2))-y=0`

C

`(d^(2)y)/(dx^(2))+(a+b)y=0`

D

`(d^(2)y)/(dx^(2))+(a-b)y=0`

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To find the differential equation for which \( y = a \cos x + b \sin x \) is a solution, we will differentiate the function twice and derive the corresponding differential equation step by step. ### Step 1: Differentiate \( y \) with respect to \( x \) Given: \[ y = a \cos x + b \sin x \] ...
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