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A capacitor of 4muF is connected as shwo...

A capacitor of 4`muF` is connected as shwon in the figure. The internal resistance of the battery is `0.5Omega`. The amount of charge on the capacitor plates will be

A

0

B

`4muC`

C

`16muC`

D

`8muC`

Text Solution

Verified by Experts

The correct Answer is:
D
Current flows through `2Omega` resistance from left to right, is given by,
`I=(V)/(R+r)=(2.5V)/(2+0.5)=1A`
The potential difference across `2Omega` resistance `V=IR=1xx2=2V` ltbgt Since, capacitor is in parallel with `2Omega` resistance, so it also has 2V potential difference across it.
The charge on capacitor
`q=CV=(2muF)xx2V=8muC`.
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