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A capacitor has some dielectric between ...

A capacitor has some dielectric between its plates, and the capacitor is connected to a DC source. The battery is now disconnected and then the dielectric is removed. State whether the capacitance, the energy stored in it, electric field, charge stored and the voltage will increase ro remain constant.

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To solve the problem step by step, we will analyze the effects of removing the dielectric from a capacitor that has been disconnected from a DC source. ### Step 1: Understand the Initial Conditions - The capacitor initially has a dielectric material between its plates, which increases its capacitance. The capacitance \( C \) with a dielectric is given by the formula: \[ C = k \frac{\varepsilon_0 A}{d} \] where \( k \) is the dielectric constant, \( \varepsilon_0 \) is the permittivity of free space, \( A \) is the area of the plates, and \( d \) is the distance between the plates. ...
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Knowledge Check

  • A parallel plate capacitor without any dielectric within its plates, has a capacitance C, and is connected to a battery of emf V. The battery is disconnected and the plates of the capacitor are pulled apart until the separation between the plates is doubled. What is the work done by the agent pulling the plates apart, in this process ?

    A
    `1/2CV^(2)`
    B
    `3/2CV^(2)`
    C
    `-3/2CV^(2)`
    D
    `CV^(2)`
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