Find the equation of tangent to the curve `x=sin3t , y=cos2t\ \ ` at `t=pi/4`

Explanation

To find the equation of the tangent to the curve defined by the parametric equations \( x = \sin(3t) \) and \( y = \cos(2t) \) at \( t = \frac{\pi}{4} \), we will follow these steps:

### Step 1: Find the point on the curve at \( t = \frac{\pi}{4} \)

1. **Calculate \( x \)**:
\[ x = \sin(3t) = \sin\left(3 \cdot \frac{\pi}{4}\right) = \sin\left(\frac{3\pi}{4}\right) = \frac{1}{\sqrt{2}} \]
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