Find the area of circle `4x^2+4y^2=9` which is interior to the parabola `x^2=4y`

Explanation

To find the area of the circle \(4x^2 + 4y^2 = 9\) that lies interior to the parabola \(x^2 = 4y\), we will follow these steps:

### Step 1: Rewrite the equations
First, we rewrite the equation of the circle in standard form:
\[ x^2 + y^2 = \frac{9}{4} \]
This represents a circle with a radius of \(\frac{3}{2}\) and centered at the origin (0, 0).
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