Find the distance of the plane `3x- 4y+12 z=3` from the origin.

Explanation

To find the distance of the plane given by the equation \(3x - 4y + 12z = 3\) from the origin, we can use the formula for the distance \(d\) from a point \((x_1, y_1, z_1)\) to a plane defined by the equation \(Ax + By + Cz + D = 0\):

\[ d = \frac{|Ax_1 + By_1 + Cz_1 + D|}{\sqrt{A^2 + B^2 + C^2}} \]

### Step-by-Step Solution:

...