Show that the right-circular cone of least curved surface and given volume has an altitude equal to `sqrt(2)` times the radius of the base.

Explanation

To show that the right-circular cone of least curved surface area for a given volume has an altitude equal to \( \sqrt{2} \) times the radius of the base, we can follow these steps:

### Step-by-Step Solution:

1. **Define Variables**:
Let the radius of the base of the cone be \( r \), the height (altitude) be \( h \), and the slant height be \( l \).

2. **Volume of the Cone**:
...