Find the value of k so that the function f defined by `f(x)={(kcosx)/(pi-2x),3\ \ \ ,\ \ \ \ \ \ \ \ \ \ "if"\ \ x\ !=pi/2"if"\ x=pi/2` is continuous at `x=pi/2`

Explanation

To find the value of \( k \) such that the function

\[
f(x) =
\begin{cases}
\frac{k \cos x}{\pi - 2x} & \text{if } x \neq \frac{\pi}{2} \\
3 & \text{if } x = \frac{\pi}{2}
\end{cases}
...