Solve : `tan^(-1)2x+tan^(-1)3x=pi/4`

Explanation

To solve the equation \( \tan^{-1}(2x) + \tan^{-1}(3x) = \frac{\pi}{4} \), we can follow these steps:

### Step 1: Use the formula for the sum of inverse tangents
We know that:
\[ \tan^{-1}(A) + \tan^{-1}(B) = \tan^{-1}\left(\frac{A + B}{1 - AB}\right) \quad \text{if } AB < 1 \]
Here, let \( A = 2x \) and \( B = 3x \). Thus, we can rewrite the equation as:
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