If `A` is a square matrix such that `A^2=I` , then find the simplified value of `(A-I)^3+(A+I)^3-7Adot`

Explanation

To solve the problem, we need to simplify the expression \((A-I)^3 + (A+I)^3 - 7A\) given that \(A^2 = I\).

### Step 1: Expand \((A-I)^3\)

Using the binomial expansion formula, we can expand \((A-I)^3\):

\[
(A-I)^3 = A^3 - 3A^2I + 3AI^2 - I^3
...