Using integration find the area of the region bounded by the curves `y=sqrt(4-x^2),x^2+y^2-4x=0` and the x-axis.

Explanation

To find the area of the region bounded by the curves \( y = \sqrt{4 - x^2} \), \( x^2 + y^2 - 4x = 0 \), and the x-axis, we will follow these steps:

### Step 1: Identify the curves
The first curve, \( y = \sqrt{4 - x^2} \), represents the upper half of a circle with center at the origin (0,0) and radius 2. The second curve, \( x^2 + y^2 - 4x = 0 \), can be rewritten as \( (x - 2)^2 + y^2 = 4 \), which represents a circle centered at (2,0) with radius 2.

### Step 2: Find points of intersection
To find the area bounded by these curves, we first need to determine their points of intersection. We set \( \sqrt{4 - x^2} = \sqrt{4 - (x - 2)^2} \).

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