Calculate the equilibrium constant for the reaction at 298 K
`Zn(s)+Cu^(2+)(aq)harr Zn^(2+)(aq)+Cu(s)`
Given` " " E_(Zn^(2+)//Zn)^(@)=-0.76 V` and `E_(Cu^(2+)//Cu)^(@)=+0.34 V`

Explanation

To calculate the equilibrium constant for the reaction at 298 K:

**Given Reaction:**
\[ \text{Zn(s)} + \text{Cu}^{2+}(aq) \rightleftharpoons \text{Zn}^{2+}(aq) + \text{Cu(s)} \]

**Given Standard Reduction Potentials:**
- \( E^\circ_{\text{Zn}^{2+}/\text{Zn}} = -0.76 \, \text{V} \)
- \( E^\circ_{\text{Cu}^{2+}/\text{Cu}} = +0.34 \, \text{V} \)
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