A first order reaction is `50%` complete in 50 minutes at 300 K and the same reaction is again 50% complete in 25 minutes at 350K Calculate activation energy of the reaction.

A certain reaction is 50% complete in 20 minutes at 300 K and the same reaction is again 50% complete in 5 minutes at 350 K, Calculate the activation energy if it is a first order reaction. [ R = 8.314 JK^(-1) mol^(-1) , log 4 = 0.602 ]

A first order reaction is 50% complete in 20 minutes. What is its rate constant ?

A first order reaction is 50% completed in 40 minutes at 300 K and in 20 minutes at 320 K. Calculate the activation energy of the reaction . (Given : log 2 = 0.3010 , log 4 = 0.6021 , R = 8.314 J K^(-1) mol^(-1) ) .

A first order reaction is 50% completed in 30 minutes at 300 K and in 10 minutes at 320 K, Calculate the activation energy of the reaction (R = 8.314 "JK mol"^(-1) .)

A first order reaction is 15% complete in 20 minutes. In what time will the reaction 60% complete ?