Draw the structure of `XeF_(2)` molecule.

Explanation

To draw the structure of the `XeF2` molecule, follow these steps:

### Step 1: Determine the Valence Electrons
- **Xenon (Xe)** is in Group 18 and has 8 valence electrons.
- **Fluorine (F)** is in Group 17 and has 7 valence electrons. Since there are 2 fluorine atoms in `XeF2`, they contribute a total of \(2 \times 7 = 14\) valence electrons.

**Total valence electrons = 8 (from Xe) + 14 (from 2 F) = 22 electrons.**

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