The density of copper is 8.95 g `cm^(-3)` .It has a face centred cubic structure .What is the radius of copper atom?
Atomic mass Cu =63.5 `gmol^(-1)N_(A)=6.02xx10^(23) mol^(-1)`

Explanation

To find the radius of a copper atom given its density and its face-centered cubic (FCC) structure, we can follow these steps:

### Step 1: Understand the FCC Structure
In a face-centered cubic (FCC) structure, there are atoms located at each corner of the cube and at the center of each face. The contribution of atoms to the unit cell is calculated as follows:
- Each corner atom contributes \( \frac{1}{8} \) of its volume to the unit cell, and there are 8 corners.
- Each face-centered atom contributes \( \frac{1}{2} \) of its volume to the unit cell, and there are 6 faces.

Thus, the total number of atoms (Z) in one FCC unit cell is:
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