Determine the osmotic pressure of a solution prepared by dissolving `2.5xx10^(-2)g" of " K_2SO_4` in 2L of water at `25^(@)C`, assuming that it is completely dissociated.
(R = 0.0821 Latm `K^(-1)`` mol^(-1)`,Molar mass of `K_2SO_4`=174 g `mol^(-1)`

Explanation

To determine the osmotic pressure of a solution prepared by dissolving \(2.5 \times 10^{-2} \, \text{g}\) of \(K_2SO_4\) in \(2 \, \text{L}\) of water at \(25^\circ C\), we will follow these steps:

### Step 1: Calculate the number of moles of \(K_2SO_4\)

The number of moles (\(n\)) can be calculated using the formula:

\[
n = \frac{\text{mass}}{\text{molar mass}}
...