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Calculate the emf of the following cell ...

Calculate the emf of the following cell at `298K`:
`Fe(s) abs(Fe^(2+)(0.001M))abs(H^+(1M))H_2(g)``(1"bar"),Pt(s)` (`"Give` `E_("Cell")^@`=`+0.44V`)

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To calculate the emf of the given cell at 298 K, we will follow these steps: ### Step 1: Identify the half-reactions The cell representation indicates that iron (Fe) is being oxidized and hydrogen ions (H⁺) are being reduced. The half-reactions are: - Oxidation half-reaction: \[ \text{Fe}(s) \rightarrow \text{Fe}^{2+} + 2e^- \] ...
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