For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction.

Explanation

To show that the time required for 99% completion of a first-order reaction is twice the time required for 90% completion, we can follow these steps:

### Step 1: Understand the first-order reaction kinetics
For a first-order reaction, the time required for a certain percentage completion can be expressed using the formula:
\[ T = \frac{2.303}{k} \log \left(\frac{A_0}{A_0 - X}\right) \]
where:
...