Write mechanism of the following reaction:
`CH_(3)CH_(2)OHoverset(HBr)toCH_(3)CH_(2)Br+H_(2)O`

Explanation

To write the mechanism for the reaction of ethanol (CH₃CH₂OH) with hydrobromic acid (HBr) to form bromoethane (CH₃CH₂Br) and water (H₂O), we can break it down into several key steps:

### Step 1: Protonation of Ethanol
Ethanol (CH₃CH₂OH) has a lone pair of electrons on the oxygen atom. When HBr is added, the hydrogen ion (H⁺) from HBr will protonate the oxygen atom of ethanol. This step increases the electrophilicity of the ethanol.

**Reaction:**
\[ \text{CH}_3\text{CH}_2\text{OH} + \text{H}^+ \rightarrow \text{CH}_3\text{CH}_2\text{OH}_2^+ \]

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