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For the reaction 2N(2)O(5)(g) to 4NO(2) ...

For the reaction `2N_(2)O_(5)(g) to 4NO_(2) (g) + O_(2)(g)` , the rate of formation of `NO_(2)(g) ` is `2.8 xx 10^(-3) Ms^(-1)` . Calculate the rate of disapperance of `N_(2)O_(5)(g)`.

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To solve the problem, we need to determine the rate of disappearance of \( N_2O_5 \) based on the rate of formation of \( NO_2 \) given in the reaction: \[ 2N_2O_5(g) \rightarrow 4NO_2(g) + O_2(g) \] ### Step-by-Step Solution: ...
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For a reaction, 2N_(2)O_(5)(g) to 4NO_(2)(g) + O_(2)(g) rate of reaction is:

For the reaction, 2N_(2)O_(5) (g) rarr 4NO_(2)(g) + O_(2)(g) , the rate of formation of O_(2) is 0.032 g h^(-1) . (a) Calculate the rate of converison of N_(2)O_(5) in g h^(-1) . (b) Calculate the rate of formation of NO_(2) in g h^(-1) .

For the first order reaction 2N_(2)O_(5)(g) rarr 4NO_(2)(g) + O_(2)(g)

For the reaction N_(2)O_(5) rarr 2NO_(2) + (1)/(2) O_(2) , the rate of disappearance of N_(2)O_(5) is 6.25 xx 10^(-3) "mol L"^(-1) s^(-1) . The rate of formation of NO_(2) and O_(2) will be respectively.

Ammonia and oxygen react at high temperature as : 4NH_3 (g) +5O_2 (g) to 4 NO(g) +6H_2 O(g) In an experiment, rate of formation of NO is 2.4 xx 10^(-3) mol L^(-) s^(-) . Calculate rate of disappearance of ammonia

For the reaction : 2N_(2)O_(5)rarr4NO2_(g)+O_(2)(g) if the concentration of NO_(2) increases by 5.2xx10^(-3)M in 100 sec, then the rate of reaction is :

For the reaction : 2N_(2)O_(5)rarr4NO_(g)+O_(2)(g) if the concentration of NO_(2) increases by 5.2xx10^(-3)M in 100 sec, then the rate of reaction is :

The rate constant k , for the reaction N_(2)O_(5)(g) rarr 2NO_(2) (g) + (1)/(2) O_(2)(g) is 2.3 xx 10^(-2) s^(-1) . Which equation given below describes the change of [N_(2)O_(5)] with time ? [N_(2)O_(5)]_(0) and [N_(2)O_(5)]_(t) correspond to concentration of N_(2)O_(5) initially and at time, t ?

XII BOARD PREVIOUS YEAR PAPER ENGLISH-XII BOARDS-Questions
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