A first order reaction is 50% completed in 40 minutes at 300 K and in 20 minutes at 320 K.
Calculate the activation energy of the reaction . (Given : log 2 = `0.3010` , log 4 = `0.6021` , R = `8.314 J K^(-1) mol^(-1)`) .

Explanation

To calculate the activation energy (Ea) of the reaction, we can follow these steps:

### Step 1: Determine the rate constants (k1 and k2)
For a first-order reaction, the half-life (t1/2) is given by the formula:

\[ t_{1/2} = \frac{0.693}{k} \]
...