Write the mechanism of the following reaction :
`2CH_(3) CH_(2) OH underset("413K")overset("Conc. "H_(2)So_(4))rarr CH_(3) CH_(2) - O - CH_(2) - CH_(3)`

Explanation

To write the mechanism for the reaction of ethanol (CH₃CH₂OH) with concentrated sulfuric acid (H₂SO₄) at 413 K to form diethyl ether (CH₃CH₂OCH₂CH₃), we can break down the process into several key steps. Here’s a step-by-step explanation of the mechanism:

### Step 1: Protonation of Ethanol
- **Description**: The first step involves the protonation of the ethanol molecule by the concentrated sulfuric acid. The oxygen atom in the hydroxyl group of ethanol has lone pairs of electrons that can accept a proton (H⁺).
- **Reaction**:
\[ \text{CH}_3\text{CH}_2\text{OH} + \text{H}^+ \rightarrow \text{CH}_3\text{CH}_2\text{OH}_2^+ \]
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