Consider the reaction
`Cr_(2)O_(7)^(2-)+14H^(+)6e^(-)rarr2Cr^(3+)+8H_(2)O`
What is the quantity of electricity in coulombs needed to reduce 1 mole of `Cr_(2)O_(7)^(2)`?

Explanation

To find the quantity of electricity in coulombs needed to reduce 1 mole of `Cr_(2)O_(7)^(2-)`, we can follow these steps:

### Step 1: Identify the Reaction
The given reaction is:
\[ \text{Cr}_{2}\text{O}_{7}^{2-} + 14\text{H}^{+} + 6\text{e}^{-} \rightarrow 2\text{Cr}^{3+} + 8\text{H}_{2}\text{O} \]

From this reaction, we can see that 6 electrons are required to reduce 1 mole of `Cr_(2)O_(7)^(2-)`.

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