Silver crystallises in a fcc lattice. The edge length of its unit is `4.077xx10^(-8)cm` and its density is `10.5g cm^(-3)`. Claculate on this basis of the atomic mass of silver `(N_(A)=6.02xx10^(23) "mol"^(-1))`

Explanation

To calculate the atomic mass of silver based on the given data, we will follow these steps:

### Step 1: Understand the FCC Lattice Structure
In a face-centered cubic (FCC) lattice:
- There are 8 atoms located at the corners of the cube.
- There are 6 atoms located at the face centers of the cube.

Each corner atom contributes \( \frac{1}{8} \) of an atom to the unit cell, and each face-centered atom contributes \( \frac{1}{2} \) of an atom to the unit cell.
...