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A 10% solution (by mass) of sucrose in ...

A 10% solution (by mass) of sucrose in water has freezing point of 269.15 K. Calculate freezing point of 10% glucose in water, if freezing point of pure is 273.15 K (Given molar mass of sucrose= 342 g `mol^(-1)`, Molar mass of glucose =180 g `mol^(-1)`).

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To solve the problem of calculating the freezing point of a 10% glucose solution in water, we will follow these steps: ### Step 1: Understand the given data - Freezing point of pure water (T0) = 273.15 K - Freezing point of 10% sucrose solution (Tf) = 269.15 K - Molar mass of sucrose = 342 g/mol - Molar mass of glucose = 180 g/mol ...
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(a) A 10% solution (by mass) of sucrose in water has freezing point of 269.15K. Calculate the freezing point of 10% glucose in water, if the freezing point of pure water is 273.15K. Given: (molar mass of sucrose=342 g mol^(-1) ) (Mola mass of glucose =180g mol^(-1) ) (b) Define the following terms: (i) Molality (m) (ii) Abnormal molar mass

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A 5% solution (w/W) of cane sugar (molar mass = 342 g mol^(-1) ) has freezing point 271 K. What will be the freezing point of 5% glucose (molar mass = 18 g mol^(-1) ) in water if freezing point of pure water is 273.15 K ?

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XII BOARD PREVIOUS YEAR PAPER ENGLISH-XII BOARDS-Set I
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