Draw the structural formulae of molecules of following compounds :
(i)` BrF_(3)` and (ii)` XeF_(4)`

Explanation

To draw the structural formulae of the compounds BrF₃ and XeF₄, we will follow these steps:

### Step 1: Draw the structure of BrF₃
1. **Identify the central atom**: In BrF₃, bromine (Br) is the central atom.
2. **Count the valence electrons**: Bromine has 7 valence electrons, and each fluorine (F) has 7 valence electrons. Therefore, the total number of valence electrons is:
\[ 7 + 3 \times 7 = 28 \text{ valence electrons} \]
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