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100 mg of a protein was disoved in just ...

100 mg of a protein was disoved in just enough water to make 10 mL of the solution. If the solution has an osmotic pressure of 13.3 mm Hg at `25^(@)C`, what is the mass of prtein `(R=0.0821 L atm mol^(-1)K^(-1))`

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To solve the problem, we need to find the molecular weight of the protein using the given osmotic pressure. We will follow these steps: ### Step 1: Convert the mass of protein from mg to g Given mass of protein = 100 mg To convert mg to g, we divide by 1000: \[ \text{Mass of protein in grams} = \frac{100 \text{ mg}}{1000} = 0.1 \text{ g} \] ### Step 2: Convert osmotic pressure from mm Hg to atm ...
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