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A voltaic cell is set up at 25^(@)C with...

A voltaic cell is set up at `25^(@)C` with the following half cells :
`Ag^(+) (0.001M)` | Ag and `Cu^(2+)(0.10 M)|Cu`
What would be the voltage of this cell ? `(E_("cell")^(@) = 0.46 V)`

Text Solution

AI Generated Solution

To find the voltage of the voltaic cell set up with the given half-cells, we will follow these steps: ### Step 1: Identify the half-reactions The half-reactions for the voltaic cell are: - **Oxidation at the anode**: \( \text{Cu} \rightarrow \text{Cu}^{2+} + 2e^- \) - **Reduction at the cathode**: \( \text{Ag}^{+} + e^- \rightarrow \text{Ag} \) ### Step 2: Write the balanced overall cell reaction ...
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