A solution prepared by dissolving `1.25g` of oil of winter green (methyl sallicylate) in `99.0g` of benzene has a boiling point of `80.31^(@)C`. Determine the molar mass of this compound. (`B.P.` of pure benzene `=80.10^(@)C` and `K_(b)` for benzene `=2.53^(@)C kg "mol".1`)

Explanation

To determine the molar mass of oil of winter green (methyl salicylate) from the given data, we will follow these steps:

### Step 1: Write down the given data
- Mass of solute (methyl salicylate) = 1.25 g
- Mass of solvent (benzene) = 99.0 g
- Boiling point of pure benzene (T_b) = 80.10 °C
- Boiling point of solution (T_b_solution) = 80.31 °C
- K_b for benzene = 2.53 °C kg/mol
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