A copper - silver cell is set up. The copper ion concentrations is `0.10` M. The concentration of silver ion is not known. The cell potential when measured was `0.422` V. Determine the concentration of silver ions in the cell.
`Given " "E^(@)Ag^(+)//Ag=+0.80 V,E^(@)Cu^(2+)//Cu=+0.34 V`

Explanation

To determine the concentration of silver ions in a copper-silver cell, we can follow these steps:

### Step 1: Write the half-reactions
In this electrochemical cell, we have the following half-reactions:

- **Anode (oxidation)**:
\[
\text{Cu} \rightarrow \text{Cu}^{2+} + 2\text{e}^-
...