What happens when bromine attacks `CH_(2)=CH-CH_(2)-C-= CH`?

Explanation

To determine what happens when bromine attacks the compound \( CH_2=CH-CH_2-C \equiv CH \), we need to analyze the reaction step by step.

### Step 1: Identify the Structure
The compound \( CH_2=CH-CH_2-C \equiv CH \) consists of an alkene (double bond) and an alkyne (triple bond). The structure can be represented as follows:
- The first part \( CH_2=CH \) indicates a double bond between the first two carbon atoms.
- The second part \( C \equiv CH \) indicates a triple bond between the last two carbon atoms.

### Step 2: Reaction with Bromine
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