Why is t- butyl bromide more reactive towards `S_N 1` reaction as compared to n- butyl bromide?

Explanation

To understand why t-butyl bromide is more reactive towards the \( S_N1 \) reaction compared to n-butyl bromide, we need to analyze the structures and the stability of the carbocations formed during the reaction.

### Step 1: Identify the Structures
- **Tertiary Butyl Bromide (t-butyl bromide)**: The structure is \( (CH_3)_3CBr \).
- **n-Butyl Bromide**: The structure is \( CH_3CH_2CH_2Br \).

### Step 2: Understand the Mechanism of \( S_N1 \) Reactions
The \( S_N1 \) reaction mechanism involves two main steps:
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