A solution of `CuSO_(4)` is electroysed for 10 minutes with a current of 1.5 amperes. What is the mass of copper deposited at the cathode ?
(Molar mass of `Cu=63.5 g//mol)`

Explanation

To find the mass of copper deposited at the cathode during the electrolysis of a `CuSO4` solution, we can follow these steps:

### Step 1: Convert Time to Seconds
The time given is 10 minutes. We need to convert this into seconds.

\[ \text{Time (t)} = 10 \text{ minutes} \times 60 \text{ seconds/minute} = 600 \text{ seconds} \]
...