A copper-silver cell is set up. The copper ion concentration in it is 0.10 M. The concentration of silver ions is not known.The cell potential measured is 0.422 V. Determine the concentration of silver ions in the cell. [Given `E_(Ag^(+)//Ag)^(@)=0.80,E_(Cu^(2+)//Cu)^(@)=+0.34 V]`

Explanation

To determine the concentration of silver ions in a copper-silver cell, we will follow these steps:

### Step 1: Write the half-reactions
The half-reactions for the copper-silver cell are:
- At the anode (oxidation):
\[ \text{Cu} \rightarrow \text{Cu}^{2+} + 2\text{e}^- \]
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